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随着洛菲菲的到来，原本平衡且平淡的表象被彻底打破，宿命使然洛菲菲成了史上最惨穿越女主，更莫名其妙的成了弱鸡反派大boss。寒冷的北风吹过，尹旭心中分外温暖，在自己最失意的时候竟然有人愿意主动投效，这份感动可谓是雪中送炭。又名《月影之下》、《难以抉择的爱》，Papoo（Margie饰）刚留学回来，她已经在国外念了十年书，但却门门挂科。Papoo有个同父异母的妹妹叫Burana，她们是截然不同的两个人。Burana斯文得体，学习认真，而且很听妈妈的话。因此，继母Karaked十分受不了Papoo没有责任心，而且占有欲极强。每次吵架，Papoo都毫不客气地跟Karaked顶嘴。因为Papoo觉得Karaked和妹妹抢走了她的父亲和家庭。Papoo小时候与奶奶同居，直到奶奶去世，她才搬去跟父亲和继母住。但Papoo上的是寄宿学校，这更让她觉得自己在这个“新家”是多余的。该剧由《劳拉之谜》（The Mysteries of Laura）、《绿箭侠》（Arrow）和《闪电侠》（The Flash）制片人Greg Berlanti开发，实际编剧为来自《洛城公寓》的Martin Gero。故事描述一个浑身赤裸的、失去记忆的美貌女人（Jaimie Alexander）爬出时代广场上的一个旅行袋，其身体布满刚刚印上去不久的复杂纹身（看上去像是某种地图）。Jane Doe（无名氏）不知道那些纹身的含义，更不清楚自己的身份和来历，但有一个谜团令所有人都感到震惊：她后背上赫然印着联邦探员Kurt Weller（Sullivan Stapleton）的名字，仿佛那是某种「装饰」。上级命令Weller组建一个危机事件反应小组（Critical Incident Response Group，简称CIRG）对这个神秘女人进行调查。在危机四伏的调查过程中，Weller将逐渐了解Jane Doe的真实身份及一个超出他想象的大型犯罪阴谋。At present, what methods do we take to solve the attack? The first method shortens the waiting time and deletes the illegal request data packets waiting in the waiting queue as soon as possible. The second method is that the first handshake message is not put into the waiting queue. We return a 32-bit unsigned integer to the client as the Seq of the second handshake. The integer is obtained by adding a serial number of the server to the parameters requested by the user (including the requested address, port, etc.). If it is a normal user, it adds 1 as ACK after receiving this integer and returns it to the server. After receiving the data, the server subtracts 1 from this ACK and then performs inverse operation to obtain various parameters. Finally, the data sent out are compared. If they are completely consistent, it means that it is an effective response and stored in the corresponding data structure, otherwise it is not. Through this method, illegal requests cannot occupy system resources.